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Problem with .NET XMLHTTPREQUEST
EurgArot
Member Posts: 2
Hi everyone,
i have a problem with this script to make an api call (Get) to the google maps web service. In this way it releases me a status other than 200. Through this script i would like the responce to be loaded in an xml witch i then pass to functions that decode and populate fields in the table. Thank you in advance, I await your answers.
The endpoint is correct because i run this api with other software and get status = 200 and release the xml.
The code of the script is this:
Variable :
DotNetXmlHttp=
MSXML.XMLHTTPRequestClass.'Microsoft.MSXML, Version=8.0.0.0, Culture=neutral
XMLResponseDoc =
System.Xml.XmlDocument.'System.Xml, Version=4.0.0.0, Culture=neutral
Procedure:
IF ISNULL(DotNetXmlHttp) THEN
DotNetXmlHttp := DotNetXmlHttp.XMLHTTPRequestClass;
DotNetXmlHttp.open('GET',ENDPOINT,0,'','');
DotNetXmlHttp.setRequestHeader('ProxyServer','<CURRENT_USER>');
DotNetXmlHttp.setRequestHeader('Timeout','30000');
XMLResponseDoc := XMLResponseDoc.XmlDocument();
IF DotNetXmlHttp.status = 200 THEN
i have a problem with this script to make an api call (Get) to the google maps web service. In this way it releases me a status other than 200. Through this script i would like the responce to be loaded in an xml witch i then pass to functions that decode and populate fields in the table. Thank you in advance, I await your answers.
The endpoint is correct because i run this api with other software and get status = 200 and release the xml.
The code of the script is this:
Variable :
DotNetXmlHttp=
MSXML.XMLHTTPRequestClass.'Microsoft.MSXML, Version=8.0.0.0, Culture=neutral
XMLResponseDoc =
System.Xml.XmlDocument.'System.Xml, Version=4.0.0.0, Culture=neutral
Procedure:
IF ISNULL(DotNetXmlHttp) THEN
DotNetXmlHttp := DotNetXmlHttp.XMLHTTPRequestClass;
DotNetXmlHttp.open('GET',ENDPOINT,0,'','');
DotNetXmlHttp.setRequestHeader('ProxyServer','<CURRENT_USER>');
DotNetXmlHttp.setRequestHeader('Timeout','30000');
XMLResponseDoc := XMLResponseDoc.XmlDocument();
IF DotNetXmlHttp.status = 200 THEN
0
Answers
URL = Endpoint
XMLHTTP = Microsoft XML, v3.0.XMLHTTP
XMLDoc = Microftsoft XML, v.6.0.DOMDocument60
CLEAR(XMLHTTP);
CLEAR(XMLDoc);
CREATE(XMLHTTP);
CREATE(XMLDoc);
XMLHTTP.open('Get', URL, FALSE);
XMLHTTP.send(XMLString);
XMLDoc.load(XMLHTTP.responseBody);
FileName := 'c:\Temp\XMLFile_' + DELCHR(FORMAT(TODAY),'=','-') + DELCHR(FORMAT(TIME),'=',':') +'.xml';
XMLDoc.save(FileName);