How to call a job in a job

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  Harish Member Posts: 172

  2005-07-22

  Hi,
  
  Just a suggestion - please don't use jobs in such a manner. Instead use class. Jobs are meant for temporary tasks.
  
  But coming to your query, you can use menuitem for calling jobs. I don't have Axapta in front of me. But it goes something like this -
  
  MenuFunction mibuso = new MenuFunction ("<Name of job>", type);
  mibuso.run();
  
  HTH,
  
  Harish Mohanbabu

  Harish Mohanbabu
  Long way to go before I sleep..

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  terabyte Member Posts: 3

  2005-08-09

  Hi Harish,
  
  The MenuFunction can only be used to execute the MenuItem type such as Action, Output and Display, and it can't be use to call jobs.
  
  Please correct me if i'm wrong.
  
  
  Regards,
  
  Terabyte

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  Harish Member Posts: 172

  2005-08-09

  Hi,
  
  Thanks for bringing this to my attention. You are right.
  
  MenuItemType (system enum that can be found under AOT -> System Documentation -> Enums) has three elements viz., Display, Output and Action.
  
  And in my last post, I just mentioned the syntax as -
  
  MenuFunction mibuso = new MenuFunction ("<Name of job>", type);
  mibuso.run();
  
  which is wrong. It should actually read as -
  
  MenuFunction mi = new MenuFunction('Job9',MenuItemType::Action);
  mi.run();
  
  Where 'Job9' is an Action type menu item. In this particular menu item, in class property, 'job' should be selected. And under 'Object' property, the appropriate job should be selected.
  
  Apologies for my earlier post.
  
  Regards,
  
  Harish Mohanbabu

  Harish Mohanbabu
  Long way to go before I sleep..

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  sanjoseguy Member Posts: 12

  2005-09-25

  hi if you didn' find the solution, you can do this way.....
  
  
  MainJob()
  {
  TreeNode treeNode = TreeNode::findNode('Jobs') ;
  TreeNode tempNode;
  ;
  
  tempNode = treeNode.AOTfindChild('Job1');
  tempNode.AOTrun();
  tempNode = treeNode.AOTfindChild('Job2');
  tempNode.AOTrun();
  
  treeNode.treeNodeRelease;
  treeNode = NULL;
  
  }
  
  Subbu

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