How to find the position of space in text

abinashphuel

Foe example I have a text

demo:='abc bcd def'.

how to find the position of space in the demo?

I have tried using strpos as

STRPOS(demo,' ')

but I always get 0 or 1 as a result.

Torben_R.

If you use one more variable it works

SubString := ' ';
String := 'abc def';
strpos(string,substring)

Torben_R.

If you use one more variable it works

SubString := ' ';
String := 'abc def';
strpos(string,substring)

abinashphuel

Torben_R. wrote: »

If you use one more variable it works

SubString := ' ';
String := 'abc def';
strpos(string,substring)

But main problem in my code was I was trimming all the spaces before getting the position by using delchar("Given String",'=')

"Given String" := ' abc def efg';
MESSAGE('---' + "Given String" + '---');
String := DELCHR("Given String",'=');
MESSAGE('---' + String + '---');

subString :=' ';
pos := STRPOS(String,' ');
MESSAGE(FORMAT(pos));

so later I change code as

"Given String" := 'abc def efg';

subString :=' ';
pos := STRPOS(Given String,subString);
MESSAGE(FORMAT(pos));

OR

"Given String" := 'abc def efg';

pos := STRPOS(Given String,' ');
MESSAGE(FORMAT(pos));

Both works for me!

Thanks