RockWithNAV wrote: »Hey Bilias,
Yes you are correct because of the Indexes and the Keys and the logic very simple.
Like suppose we have 4 Columns of 20 Byte each in the Table.
Table - C1 - C2 - C3 - C4 - Size - 80 Byte
Now say we have made 4 Keys in this table and the combination is like
1. C1,C2,C3
2. C2,C4
3. C1,C4
4. C2,C3,C4
So now if you calculate it will hit 200 Bytes.
Hope this Helps.
Thanks
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Answers
Refer to this Link
http://forum.mibuso.com/discussion/1362/maximum-number-of-fields-max-record-size
Hope this helps.
Thanks
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I had found that thread as well, but the only idea I could see mentioned in it was to add up the bytes of each of the individual fields and I was wondering if the record size was actually held somewhere within NAV?
Dave
Record Size must not be greater then 8000 Bytes.
See this screenshot
Thanks
Hope this Helps.
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Yes you can, Follow this Step -
1. Make a New Page
2. In the Table name write - Table Information
3. Make it list
4. Press Next and complete the Wizard.
5. Run the Page
6. Filter for your company and Table.
Thanks
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I tried this but I couldn't understand why the record size was different for different companies in the same database, and why some tables seemed to have a record size greater than 8K.
Sorry for the contradiction b/w the understanding. You asked Record size so i felt you are now concerned of the memory its occupying. This Table information shows the
Record Size - Average size of a record.
Size (KB) - Space table Occupies in Database.
As far as the Development environment is concerned i dont think theres any way to calculate how much fields you can more create until and unless you face that error. The point is number of fields always depends on how much of Byte you have available like if a length of 100 Byte is available you can either create 50 byte of two Fields or 10 byte of 10 Fields. You can need calculate this depending upon each fields you have created.
Thanks
Blog - https://rockwithnav.wordpress.com/
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AFAIK, there's not an easy way to do it
"Never memorize what you can easily find in a book".....Or Mibuso
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Yes you are correct because of the Indexes and the Keys and the logic very simple.
Like suppose we have 4 Columns of 20 Byte each in the Table.
Table - C1 - C2 - C3 - C4 - Size - 80 Byte
Now say we have made 8 Keys in this table and the combination is like
1. C1,C2,C3
2. C2,C4
3. C1,C4
4. C2,C3,C4
So now if you calculate it will hit 200 Bytes.
Hope this Helps.
Thanks
Blog - https://rockwithnav.wordpress.com/
Blog - rockwithnav.wordpress.com/
Twitter - https://twitter.com/RockwithNav
Facebook - https://facebook.com/rockwithnav/
Blog - rockwithnav.wordpress.com/
Twitter - https://twitter.com/RockwithNav
Facebook - https://facebook.com/rockwithnav/
Thanks again,
Dave