Common Dialog OpenFile - Default Folder To Browse?

Jonathan2708

Hi,

I'm using Codeunit 412 Common Dialog Management to prompt the user for a file. My question is can you set the OpenFile function to popup the window in a specific folder via code? You can give it a default filename, but can't see how to set a default folder.

If not is there a workaround, maybe another function to call first to set the users' default folder?

Any help appreciated,

Jonathan

kapamarou

In 412 you'll see:

CommonDialogControl.InitDir := DefaultFileName;

I guess it takes the path of the file you pass as a parameter.

Either pass your parameter differently or

copy the function as OpenFile2, add a parameter defDir and change the line to :
CommonDialogControl.InitDir := defDir;


Try it to see if it works...

Jonathan2708

Hi,

Thanks for the reply but already tried that. It simply uses the parameter as a default filename, not folder, and if you specify a backslash e.g. 'C:\WINDOWS\' then you get an error message.

Jonathan

kapamarou

I tried it like this:


I Copied OpenFile to new function OpenFile2.

I added one more parameter defdir (text 30);

I found the line:

CommonDialogControl.InitDir := DefaultFileName;

and changed it to:

CommonDialogControl.InitDir := defdir;

Then to call the function I do the following:

cu412.OpenFile2('Open','',0,'',0,'C:\program files\adobe');

Did you try it like this? When I run it it opens folder C:\program files\adobe with a blank filename.

Jonathan2708

Thanks, I've sussed it. The default folder only works if you set the default filename to blank ''.

Thanks for your help,

Jonathan

kapamarou

You're welcome.

kapamarou

Jonathan2708 wrote:

The default folder only works if you set the default filename to blank

I tried it and it also works if you pass as a filename 'file.txt' for example, along with the path parameter...