Setrange Prob.

upasanisandip

Hi ,

Can anyone know how to solve this problem.

I want the min. serial no. value in table.

so using following code but getting 10 as return value.

Actual serial no. value in table is 20.

Vehicle is a record variable of subtype Vechicle Table.


Vehicle.SETRANGE(Vehicle."Serial No.",10,300);
MESSAGE('%1',Vehicle.GETRANGEMIN("Serial No."));



Thanks in adv.



Sandip.

kriki

GETRANGEMIN gets you the minimum value of the filter you created, not the minimum value in the DB.
To get the min value, you need to create a loop to check it.

Vehicle.SETRANGE("Serial No.",10,300); 
IF Vehicle.FIND('-') THEN BEGIN
  MinSerialNo := Vehicle."Serial No.";
  REPEAT
     IF MinSerialNo > Vehicle."Serial No." THEN
      MinSerialNo := Vehicle."Serial No.";
  UNTIL Vehicle.NEXT = 0;
END;

MESSAGE('%1',MinSerialNo);

aniruddha_majumdar

Hi
Dear friend it will always give 10.
Better take on key which is sorting on Serial NO.
Do Setcurrent key
then setrange
and then find(-);
u will get the result

Soln given by kriki will also work

kriki

aniruddha_majumdar wrote:

Hi
Dear friend it will always give 10.
Better take on key which is sorting on Serial NO.
Do Setcurrent key
then setrange
and then find(-);
u will get the result

Soln given by kriki will also work

My solution is faster for writing in the table, because no extra key has to be maintained, but slower in reading, because it has to read some records.

The extra-key solution of aniruddha_majumdar is faster for reading, because with 1 read it has the correct record, but it will be slower to write in the table.

So if the code to read it has NOT to be lightening-fast for some reasons, it is best to use my solution.
If your code has to be lightening-fast (e.g. it is part of a posting-procedure), then it is best to use the extra-key-solution.

upasanisandip

ok thanks . I exactly want the same.