What is the Concept of Licensed Concurrent Users in NAV?

ishwarsharma
ishwarsharma Member Posts: 6
in General Chat
Hi,

I am unable to understand the concept of concurrent licensed users in NAV 2013 and later versions.

My NAV 2016 developer's license has 6 full user CAL.

I logged in to NAV RTC with User A's ID on my machine, and I am also able to login to the same database through a different machine using User A's ID when 5 other users (B,C,D,E,F) are already logged in to this database (and these users have opened multiple sessions) on their respective machines.

In a nutshell, 7 users are working on 7 different machines when the License permits only 6 concurrent users at a time.

These 7 users are :

User A - Machine 1

User A - Machine 2

User B - Machine 3

.

.

.

User F - Machine 7.

Please can anyone explain this, this is a bit confusing for me as the concept is still not to clear to me.

Thanks.
-Ishwar

http://ishwar-nav.blogspot.com/

Don't forget to the post(s) that solved your problem

Best Answer

Answers

  • davmac1
    davmac1 Member Posts: 1,283
    it is meant to count concurrent user ids,which it appears to be doing for you since you logged in twice.
    David Machanick
    http://mibuso.com/blogs/davidmachanick/
  • ishwarsharma
    ishwarsharma Member Posts: 6
    davmac1 wrote: »
    it is meant to count concurrent user ids,which it appears to be doing for you since you logged in twice.

    Okay. But if this thing is possible then any no. of users can work with the same user ID on different machines and we might never get the error of No. of logins. Is it?
    -Ishwar

    http://ishwar-nav.blogspot.com/

    Don't forget to the post(s) that solved your problem
  • Phenno
    Phenno Member Posts: 630
    Yes, in theory, but company will have number od problems, such as columns dissapearing/appearing, no security could be set, logs would be unuseful, etc...
  • ishwarsharma
    ishwarsharma Member Posts: 6
    Thanks for your advice Phenno :smile:
    -Ishwar

    http://ishwar-nav.blogspot.com/

    Don't forget to the post(s) that solved your problem

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