Filter percentage out of string

ReSpongebob · 2005-07-26

Hi,

I would like to filter a percentage out of a string.

Example:

String: This ring is made of 15% pure gold

The result I need:
Var1: This ring is made of pure gold
Var2: 15%

Thanks in advance!

lzr · 2005-07-26

have you tried using copystr (copy part of the string) and strpos (find first position of a given substring)?

ReSpongebob · 2005-07-26

Thanks for the reply.

I'm rather new to Navision and I don't know how I can filter a subset (0..9 |%|,) out of a string-variable.

Albertvh · 2005-07-26

Hi

You could code it like this

Text := 'this ring is made of 10% pure gold';
Text3 := Text;
WHILE STRPOS(Text3,'%') > 0 DO BEGIN
   Text3 := COPYSTR(Text3,STRPOS(Text3,' ') + 1);
   i := STRPOS(Text3,'%');
   IF (i < 6) AND
      (Text2 = '') THEN BEGIN
     Text2 := DELCHR(COPYSTR(Text3,1,i),'<>',' ');
     j := STRLEN(Text2);
   END;
END;
i := STRPOS(Text,'%');
Text1 := COPYSTR(Text,1,i - j) + COPYSTR(Text,i + 2);
MESSAGE('text = %1\Txt1 = %2\Txt2 = %3',Text,Text1,Text2);

Albert

ReSpongebob · 2005-07-26

Thanks a lot.
=D>

Filter percentage out of string

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