XML port and File name

Yes this is possible.

First create a variable of codeunit Common Dialog Management.

Then when you write code to create a new file insert function from this codeunit.open.

Example

testfile.CREATE(CDM.OpenFile(Text003,'',4,'*.xml',1));

where testfile is of datatype file.
CDM is the variable of that codeunit comman dialog Managment.
Text003 is the Window Title.
'' is the default file name.
4 is the default file type.
*.xml is the Filter String
1 is the action that is save in this case.