Converting DateFormula to Integer!!!

Hi

You can convert a datetime like a "delta" integer:

something like:

i := calcdate('<1M>', today) - today

But if the calculation involve month, for example, can return strange result:

If today is 22 of may, + 1 Month the int result is 31 days.
But if today is 22 Feb. + 1 Month the int result is 28 days.

Bye

Matteo

Hanen wrote:

Thanks but I have to get something like :
2M --> 60
45D --> 45
2Y --> 720
....................
Can you tel me how can I deal with that?

as the post above describes - you're going to have problems with 2M since not all months are 30 days. If you need it to be 60 days you'll need to code that to 60 & 2Y = 730 not 720.