Function 'CopyArray' does not work (v5.0)

when using copyarray, you have to fill all the elements of the destination array so, in this code you have
b array = 12
a array = 8
i=integer
I am going to copy 8 elements from the 12 array to the 8 array with this instruction

FOR i := 1 TO 12 DO BEGIN
  b[i] := i
END;
COPYARRAY(a,b,5);

or

FOR i := 1 TO 12 DO BEGIN
  b[i] := i
END;
COPYARRAY(a,b,1,8);

and this returns error

FOR i := 1 TO 12 DO BEGIN
  b[i] := i
END;
COPYARRAY(a,b,1,7);

DenSter wrote:

The message "Array dimensions should be identical" tells you all you need to know

I disagree. Based on the example provided in Help the array dimensions clearly do NOT have to be identical:

Example
If array1 is an integer array with dimension 10, and it contains the numbers from 1 to 10, the following command copies the numbers 6,7,8,9,10 to array2, an integer array with dimension 5.

COPYARRAY (array2,array1,6,5);

It's a very bad error message that doesn't tell you what the actual problem is.

matttrax wrote:

DenSter wrote:

The message "Array dimensions should be identical" tells you all you need to know

I disagree. Based on the example provided in Help the array dimensions clearly do NOT have to be identical:

Example
If array1 is an integer array with dimension 10, and it contains the numbers from 1 to 10, the following command copies the numbers 6,7,8,9,10 to array2, an integer array with dimension 5.

COPYARRAY (array2,array1,6,5);

It's a very bad error message that doesn't tell you what the actual problem is.

Well I have to disagree with your disagreement Matt
He's trying to put 8 elements into an array of 12, which fails because they do not have the same number of elements, the message is crystal clear to me. The example you are quoting there is copying an array of 5 (5 elements starting with element number 6) into an array of 5, which has the same number of elements. Granted the source array has 10 elements, but the command only tries to copy 5 elements into an array of 5 elements. It's a whole nother discussion as to why they wouldn't allow a small array to be copied into a larger array, but the message itself is very clear to me.

It's clear that the COPYARRAY command doesn't work, so program a little loop and you're done.

It doesn't work in a situation where you want to copy an array of 8 elements into an array of 12, and he's going to have to find an alternative.

Here's the syntax for COPYARRAY:
COPYARRAY(NewArray, Array, Position [, Length])

The last parameters is Length. If you have a 10 element array, and you want to copy 5 of its elements into a 5 element array, you specify length as 5, just like the example that specified Position=6 and Length=5 to copy into a 5 element array. At that moment, your target as well as your source are both 5 elements, and COPYARRAY will work. It doesn't look at the actual source array, but at the 5 elements you're providing.

Apparently the command doesn't like it when your source array has fewer elements than the target array, it just needs identical numbers of elements. It wants you to provide as many elements as the target array.

It works exactly the way that I expect it to work, and the message is crystal clear to me. It means that if you want to copy x elements into an array that has more than x elements, you're going to have to loop through the elements in C/AL code and assign them that way.

DenSter wrote:

It doesn't work in a situation where you want to copy an array of 8 elements into an array of 12, and he's going to have to find an alternative.

Here's the syntax for COPYARRAY:
COPYARRAY(NewArray, Array, Position [, Length])

The last parameters is Length. If you have a 10 element array, and you want to copy 5 of its elements into a 5 element array, you specify length as 5, just like the example that specified Position=6 and Length=5 to copy into a 5 element array. At that moment, your target as well as your source are both 5 elements, and COPYARRAY will work. It doesn't look at the actual source array, but at the 5 elements you're providing.

Apparently the command doesn't like it when your source array has fewer elements than the target array, it just needs identical numbers of elements. It wants you to provide as many elements as the target array.

It works exactly the way that I expect it to work, and the message is crystal clear to me. It means that if you want to copy x elements into an array that has more than x elements, you're going to have to loop through the elements in C/AL code and assign them that way.

yes, the strange thing of the function is the fact that you can't copy 3 elements in a array with max 5 elements...THIS is the thing that confused me.
about the error: you have two array of 5 elements, then you fill only the first 4 of the first array.
then you use the copyarray function to move the elements to the 2nd array and BANG!error...
the first thing I think is to take a look to array dimensions, which are the same...after that...what I have to do if i follow the error as is?

Sometimes you get sad reading threads. You haven't got a single helpful reply.

forget copyarray it not working as documented, use your own, its pretty simple:

FOR i := 1 TO ARRAYLEN(OriginalArray) DO
NewArray := OriginalArray;